Question

Sin(3pi/2-a)=-cosa Помгитте

Answer 1

Ответ:

Объяснение:

Используя формулу приведения для синуса получаем:

-cosa=-cosa

0=0

Answer 2

3()8277166666715:51676)pi

Answer 3

Sure, I'd be happy to help!

We can use trigonometric identities to solve the equation:

1. Recall the angle difference identity for sine: sin(A - B) = sin A * cos B - cos A * sin B.

2. In your equation, A = 3π/2 and B = a. So, we can rewrite the equation as follows:

sin(3π/2 - a) = sin(3π/2) * cos(a) - cos(3π/2) * sin(a).

3. Now, let's find the values of sin(3π/2) and cos(3π/2):

sin(3π/2) = -1 (sine of 3π/2 is -1). cos(3π/2) = 0 (cosine of 3π/2 is 0).

4. Replace these values in the equation:

-1 * cos(a) - 0 * sin(a) = -cos(a).

5. So, the equation becomes:

-sin(a) = -cos(a).

6. Now, to solve for 'a', we'll divide both sides by '-1' to eliminate the negative sign:

sin(a) = cos(a).

7. Finally, we can use the identity sin(θ) = cos(90° - θ) to see that this equation is satisfied when 'a' is 45 degrees or π/4 radians:

a = 45° or a = π/4 radians.

Thus, the solution to the equation is a = 45° or a = π/4 radians.