Question

Log2 6 - log2 (6/32) =

Answer 1

Ответ:

Найти значение лог. выражения.

Answer 2

Ответ:log₂ 6 - log₂ (3/16) = log₂ [6 / (3/16)] = log₂ 32 = log₂ 2⁵ = 5log₂ 2 = 5

Answer 3

To simplify the expression, we can use logarithm rules. The most relevant rule in this case is:

log_b(a) - log_b(c) = log_b(a/c)

Applying this rule to the given expression:

log2(6) - log2(6/32) = log2(6 / (6/32)) = log2(6 * (32/6)) = log2(32)

Now, we need to find the base-2 logarithm of 32. Logarithm with base 2 of a number x (log2(x)) represents the power to which 2 must be raised to get x.

2^5 = 32

So, log2(32) = 5

Therefore, the simplified expression is:

log2(6) - log2(6/32) = log2(32) = 5