Question

Решите 2x-(x+1)^2=3x^2-6

Answer 1

Ответ:

х²=1,25 х= корень из 1,25

Объяснение:

(х+1)²=х²+2х+1

2х-(х²+2х+1)=2х-х²-2х-1=-х²-1

-х²-1=3х²-6

4х²-5=0

4х²=5

х²=5/4=1,25

Answer 2

To solve the equation 2x - (x + 1)^2 = 3x^2 - 6, follow these steps:

Step 1: Expand the squared term on the left side.

2x - (x + 1)^2 = 3x^2 - 6 2x - (x^2 + 2x + 1) = 3x^2 - 6

Step 2: Remove the parentheses.

2x - x^2 - 2x - 1 = 3x^2 - 6

Step 3: Combine like terms on both sides of the equation.

(2x - 2x) - x^2 - 1 = 3x^2 - 6

• x^2 - 1 = 3x^2 - 6

Step 4: Move all terms to one side of the equation to set it to zero.

• x^2 - 1 - 3x^2 + 6 = 0

Step 5: Combine like terms.

-4x^2 + 5 = 0

Step 6: Now, isolate the x^2 term by moving the constant to the other side.

-4x^2 = -5

Step 7: Divide both sides by -4 to solve for x^2.

x^2 = 5/4

Step 8: Take the square root of both sides to find the possible values of x.

x = ±√(5/4)

Step 9: Simplify the square root.

x = ±√(5)/2

So, the solutions for the equation are:

x = √(5)/2 and x = -√(5)/2