Question

(y + 2) ^2- 2y (y + 2)​

Answer 1

$(y+2)^2-2y(y+2)=(y+2)\cdot (y+2-2y)=(y+2)\cdot (2-y)=\\\\=(2-y)(2+y)=2^2-y^2=4-y^2$

Answer 2

It looks like you want to simplify the expression $(y + 2)^2 - 2y(y + 2)$. Let's go through the steps to simplify it:

1. Start by expanding $(y + 2)^2$: $(y + 2)^2 = y^2 + 4y + 4$

2. Now distribute the -2y to both terms inside the second parentheses: $-2y(y + 2) = -2y^2 - 4y$

3. Subtract the second expression from the first: $(y^2 + 4y + 4) - (-2y^2 - 4y)$

Distribute the negative sign: $y^2 + 4y + 4 + 2y^2 + 4y$

Combine like terms: $y^2 + 2y^2 + 4y + 4y + 4$

Combine the y^2 terms and the y terms: $3y^2 + 8y + 4$

So, the simplified expression is $3y^2 + 8y + 4$.