Question

Re: 6cos 30 *- 3tg 60° + 2sin 45º;

Answer 1

Вот решение
Ответ корень из двух

Answer 2

To simplify the expression $6 \cos 30° - 3 \tan 60° + 2 \sin 45°$, we first need to evaluate each trigonometric function and then perform the arithmetic operations.

1. Evaluate $\cos 30°$: The cosine of 30 degrees can be determined using the trigonometric ratios for a 30-60-90 degree right triangle. In this case, $\cos 30° = \frac{\sqrt{3}}{2}$.

2. Evaluate $\tan 60°$: The tangent of 60 degrees can be found using the trigonometric ratios for a 30-60-90 degree right triangle. In this case, $\tan 60° = \sqrt{3}$.

3. Evaluate $\sin 45°$: The sine of 45 degrees can be determined using the trigonometric ratios for a 45-45-90 degree right triangle. In this case, $\sin 45° = \frac{\sqrt{2}}{2}$.

Now, substitute the values into the expression:

$6 \cdot \frac{\sqrt{3}}{2} - 3 \cdot \sqrt{3} + 2 \cdot \frac{\sqrt{2}}{2}$

Now, simplify each term:

$3\sqrt{3} - 3\sqrt{3} + \sqrt{2}$

The term $3\sqrt{3}$ cancels out, leaving:

$\sqrt{2}$

So, the simplified expression is $\sqrt{2}$.