Question

(x^-1)(x^+3)=(x^+1)+ x

Answer 1

Ответ:

х2+3х-х-3=х2+х

х2+3х-х-3-х2-х=0

х-3=0

х=3

Answer 2

Let's simplify the given expression step by step:

1. Distribute the exponent of -1 to the term inside the first parentheses: (x^-1)(x^+3) = (1/x)(x^+3)

2. Now, let's distribute (1/x) to the terms inside the second parentheses: (1/x)(x^+3) = (1/x) * x + (1/x) * 3

3. Simplify the above expression: (1/x) * x simplifies to 1, and (1/x) * 3 simplifies to 3/x:

1 + 3/x = (x^+1) + x

Now, the equation becomes:

1 + 3/x = x^+1 + x

To solve this equation for x, let's first get rid of the fraction by multiplying all terms by x:

x * (1 + 3/x) = x * (x^+1 + x)

Simplify:

x + 3 = x^2 + x^2

Now, let's combine like terms:

2x^2 - x - 3 = 0

Now, this is a quadratic equation in standard form. We can solve it using factoring, completing the square, or the quadratic formula. However, upon further inspection, it seems that this equation does not have simple integer solutions.

To find the values of x that satisfy the equation, you can use numerical methods or a graphing calculator. Unfortunately, I cannot provide an exact solution for x without numerical approximations or further context about the equation.