Question

8х в квадрате+х-9=0?

Answer 1

Ответ:

D = 1 - 4 * (-9) * 8 = 1 + 288 = 289

x1 = $\frac{-1 + \sqrt{289} }{8 * 2}$ = $\frac{16}{16}$ = 1

x2 = $\frac{-1 - \sqrt{289} }{8 * 2}$ = $\frac{-18}{16}$ = -1,125

Answer 2

To solve the quadratic equation 8x^2 + x - 9 = 0, we can use the quadratic formula. The quadratic formula is given as:

x = (-b ± √(b^2 - 4ac)) / 2a

Where: a = coefficient of x^2 term b = coefficient of x term c = constant term

For our equation, a = 8, b = 1, and c = -9. Plugging these values into the quadratic formula, we get:

x = (-(1) ± √((1)^2 - 4 * 8 * (-9))) / 2 * 8 x = (-1 ± √(1 + 288)) / 16 x = (-1 ± √289) / 16 x = (-1 ± 17) / 16

Now we have two possible solutions:

1. x = (-1 + 17) / 16 = 16 / 16 = 1
2. x = (-1 - 17) / 16 = -18 / 16 = -9/8

So, the solutions to the equation 8x^2 + x - 9 = 0 are x = 1 and x = -9/8.