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Решите пж: 1.{2x+3>x-1 {9x-5<4x 2.{2-4y>2y-10 {3>2(y+3) Смотреть ответ lizagrugorieva163412 lizagrugorieva163412 Ответ: {2x+3>x-1 {9x-5<4x {x>-4 {5x<5 {x>-4 {x<1 Ответ: x∈(-4;1) {2-4y>2y-10 {3>2(y+3) {2y+4y<2+10 {y+3<1,5 {6y<12 {y<-1,5 {y<2 {y<-1,5 Объяснение: Новые вопросы в Алгебра решите пожалуйста ...​ упростить выражение ​ помогите пожалуйста обчислить.там если что в начале 3⁶заранее спасибо ​ Здравствуйте друзья ! Помогите пожалуйста с Алгеброй! Решите уравнение (x²+x)²+2(x²+x)-8=0​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Для решения уравнений и неравенств, давайте разберем каждое из них по порядку:

1. {2x+3>x-1 {9x-5<4x

Для первого уравнения: 2x + 3 > x - 1

Вычитаем x из обеих частей уравнения: 2x - x + 3 > x - x - 1 x + 3 > -1

Вычитаем 3 из обеих частей уравнения: x + 3 - 3 > -1 - 3 x > -4

Таким образом, решением первого уравнения является x > -4.

Для второго уравнения: 9x - 5 < 4x

Вычитаем 4x из обеих частей уравнения: 9x - 5 - 4x < 4x - 4x 5x - 5 < 0

Прибавляем 5 к обеим частям уравнения: 5x - 5 + 5 < 0 + 5 5x < 5

Делим обе части на 5 (учитывая, что деление на положительное число не меняет знак неравенства): x < 1

Таким образом, решением второго уравнения является x < 1.

Теперь объединим результаты, чтобы получить окончательное решение для системы неравенств: x > -4 (из первого уравнения) x < 1 (из второго уравнения)

Таким образом, решением системы неравенств будет интервал: x ∈ (-4, 1).

2. {2-4y > 2y-10 {3 > 2(y+3)

Для первого уравнения: 2 - 4y > 2y - 10

Прибавляем 4y к обеим частям уравнения: 2 - 4y + 4y > 2y - 10 + 4y 2 > 6y - 10

Прибавляем 10 к обеим частям уравнения: 2 + 10 > 6y - 10 + 10 12 > 6y

Делим обе части на 6 (учитывая, что деление на положительное число не меняет знак неравенства): 2 > y

Таким образом, решением первого уравнения является y < 2.

Для второго уравнения: 3 > 2(y + 3)

Раскрываем скобку: 3 > 2y + 6

Вычитаем 6 из обеих частей уравнения: 3 - 6 > 2y + 6 - 6 -3 > 2y

Делим обе части на 2 (учитывая, что деление на отрицательное число меняет знак неравенства): -3 / 2 > y

Таким образом, решением второго уравнения является y < -3/2.

Теперь объединим результаты, чтобы получить окончательное решение для системы неравенств: y < 2 (из первого уравнения) y < -3/2 (из второго уравнения)

Таким образом, решением системы неравенств будет y < -3/2.

Обратите внимание, что результаты указаны в виде интервалов, так как мы ищем диапазоны значений переменных, которые удовлетворяют обоим неравенствам.