Question

5x^2/x+5 - 6x^2-3x-30/x+5 - 5-2x^2-7x/x+5​

Answer 1

Ответ:

x+5

Объяснение:

$\frac{5x^2}{x+5}-\frac{6x^2-3x-30}{x+5}-\frac{5-2x^2-7x}{x+5}=\\ \\ =\frac{5x^2-6x^2+3x+30-5+2x^2+7x}{x+5} =\frac{x^2+10x+25}{x+5} =\\ \\ \frac{(x+5)^2}{x+5}=x+5$

Answer 2

It looks like you've provided a mathematical expression with fractions involving variables. Let's simplify this expression step by step:

The given expression is: (5x^2)/(x+5) - (6x^2-3x-30)/(x+5) - (5-2x^2-7x)/(x+5)

Step 1: Combine the fractions over the common denominator (x+5): [(5x^2) - (6x^2-3x-30) - (5-2x^2-7x)] / (x+5)

Step 2: Distribute the negative sign to the terms within the parentheses: 5x^2 - 6x^2 + 3x + 30 - 5 + 2x^2 + 7x / (x+5)

Step 3: Combine like terms: (5x^2 - 6x^2 + 2x^2) + (3x + 7x) + (30 - 5) / (x+5)

Simplifying the terms gives: x^2 + 10x + 25 / (x+5)

Step 4: Factor the numerator: (x + 5)^2 / (x+5)

Step 5: Cancel out the common factor of (x+5) in the numerator and denominator: x + 5

So, the simplified expression is: x + 5.