Question

4a-a³=ax²+2ax+a=пж!​пж!пж!пж!​

Answer 1

Ответ:

а(4-а²) = а(2-а)(2+а)

ах²+ах+ах+а = ах(х+1)+а (х+1) = (х+1)(ах+а) = (х+1)(х+1)а = (х+1)²а

Объяснение:

Answer 2

It seems like you've provided an equation:

4a - a³ = ax² + 2ax + a

If you're looking for a solution or some assistance with this equation, I can help you with that. To start, it appears to be a quadratic equation in terms of variable "a". The equation might be solved by rearranging terms, factoring, or using other methods. Could you please clarify what you'd like to do with this equation? Are you looking for a specific solution or trying to simplify it?