Question

(2х + 6)(7 – 4х) = (2 – х)(8х + 1) + 15

Answer 1

умножаем друг на друга.

14x-8x^2+42-24x=16x+2-8x^2-x+15 (-8x^2 и 8x^2 сокращаются)

2) иксы в левую часть, а числа в правую часть.

14x-24x-16x+x=-42+15

-26x=-27 (минусы уходят, так как - на - = + (положительное)

x= 27/26 (на всякий случай перепроверь, ответ дробью получается)

Answer 2

To solve the given equation, we'll start by expanding both sides and then simplifying the equation:

Given equation: $(2x + 6)(7 - 4x) = (2 - x)(8x + 1) + 15$

Let's start by expanding each side step by step:

Left side: $(2x + 6)(7 - 4x) = 2x \cdot 7 + 2x \cdot (-4x) + 6 \cdot 7 + 6 \cdot (-4x)$ $= 14x - 8x^2 + 42 - 24x$ $= -8x^2 - 10x + 42$

Right side: $(2 - x)(8x + 1) + 15 = 2 \cdot 8x + 2 \cdot 1 - x \cdot 8x - x \cdot 1 + 15$ $= 16x + 2 - 8x^2 - x + 15$ $= -8x^2 + 15x + 17$

So, the expanded equation becomes: $-8x^2 - 10x + 42 = -8x^2 + 15x + 17$

Now, let's simplify the equation by moving all terms to one side:

$-8x^2 - 10x + 42 + 8x^2 - 15x - 17 = 0$

Simplifying further: $-25x + 25 = 0$

Now, let's isolate $x$ on one side of the equation: $-25x = -25$

Dividing both sides by -25: $x = 1$

So, the solution to the equation is $x = 1$.