Question

(8y+12) (1,4-0,7y)=0

Answer 1

Ответ:

(8y+12) (1,4-0,7y)=0

11,2y - 5,6y² +16,8 -8,4y=0

5,6y² - 2,8у - 16,8 =0

28у² - 14у - 84=0

2у²- у - 6 = 0

D = 1 +48 = 49

y= (1 +7)/4 = 2

y= (1- 7)/4 = -1,5

Answer 2

It looks like you have a quadratic equation that you'd like to solve for the value(s) of "y." The equation you provided is:

(8y + 12) * (1.4 - 0.7y) = 0

To solve for "y," we can set each factor equal to zero and solve for "y" in each case:

1. Setting 8y + 12 = 0: Subtract 12 from both sides: 8y = -12 Divide both sides by 8: y = -12 / 8 y = -1.5

2. Setting 1.4 - 0.7y = 0: Subtract 1.4 from both sides: -0.7y = -1.4 Divide both sides by -0.7: y = -1.4 / -0.7 y = 2

So, the solutions for "y" that satisfy the equation are y = -1.5 and y = 2.