Question

(2x−3)(4x2+6x+9)+19=0 . x=

Answer 1

Ответ:

у тебя ошибка в написании примера. исправь и тогда можно будет решить

Answer 2

To solve the given equation:

(2x−3)(4x^2+6x+9)+19=0

We can start by expanding the left side of the equation:

(2x - 3)(4x^2 + 6x + 9) + 19 = 8x^3 + 12x^2 + 18x^2 + 24x - 12x + 18 + 19 = 8x^3 + 30x^2 + 12x + 37

Now the equation becomes:

8x^3 + 30x^2 + 12x + 37 = 0

This is a cubic equation. Cubic equations can be challenging to solve directly, but you can use numerical methods or software to find approximate solutions. In this case, since you're looking for a specific value of x, you might use numerical methods such as Newton's method or use software like MATLAB or Wolfram Alpha to find a numerical approximation of the solutions. Keep in mind that the solutions could be complex numbers as well, as cubic equations can have real and/or complex roots.