Question

If x+y=4 and y-z=-3 then find the value of xy-xz+y^2-yz -----ДАМ 30 БАЛЛОВ ПОМОГИТЕ!!!!!!

Answer 1

Ответ: -12

Объяснение:

$xy-xz+y^{2}-yz=x(y-z)+y(y-z)=(y-z)(x+y)=-3*4=-12$

Answer 2

Let's break down the problem step by step using the given equations:

1. x + y = 4
2. y - z = -3

From the first equation, we can solve for x in terms of y: x = 4 - y

Now we can substitute this value of x into the expression you provided: xy - xz + y^2 - yz = y(4 - y) - z(4 - y) + y^2 - yz

Distribute the terms: 4y - y^2 - 4z + yz + y^2 - yz

Simplify the terms: 4y - 4z

Now, we need to solve for y and z in terms of each other using the second equation: y - z = -3 y = -3 + z

Substitute this value of y into the simplified expression: 4(-3 + z) - 4z -12 + 4z - 4z -12

So, the value of xy - xz + y^2 - yz is -12.