Question

4-5(0,2m-2k)=3(3k+2)+2m4(k-4m)-(2k+m)=3-2(2k+m)

Answer 1

Ну будет равно 2k+m.

Answer 2

It looks like you've provided a system of equations. To solve for the variables $m$ and $k$, we can follow these steps:

Equation 1: $4 - 5(0.2m - 2k) = 3(3k + 2) + 2m$ Equation 2: $4(k - 4m) - (2k + m) = 3 - 2(2k + m)$

Let's solve for $m$ and $k$ step by step:

Equation 1: Start by simplifying the left side: $4 - 5(0.2m - 2k) = 4 - 1(1m - 10k) = 4 - m + 10k$

Now simplify the right side: $3(3k + 2) + 2m = 9k + 6 + 2m$

So, we have the equation: $4 - m + 10k = 9k + 6 + 2m$

Move all the terms involving $m$ to one side: $-m - 2m = 9k - 10k + 6 - 4$ $-3m = -k + 2$

Divide by -3: $m = \frac{k - 2}{3}$ ... (Equation A)

Equation 2: Start by simplifying the left side: $4(k - 4m) - (2k + m) = 4k - 16m - 2k - m = 2k - 17m$

Now simplify the right side: $3 - 2(2k + m) = 3 - 4k - 2m$

So, we have the equation: $2k - 17m = 3 - 4k - 2m$

Combine like terms involving $k$ and $m$: $2k + 4k = 17m - 2m + 3$ $6k = 15m + 3$ $2k = 5m + 1$

Divide by 2: $k = \frac{5m + 1}{2}$ ... (Equation B)

Now you have a system of equations (Equation A and Equation B) with $m$ and $k$ expressed in terms of each other. You can substitute the expression for $k$ from Equation B into Equation A or vice versa to find the values of $m$ and $k$.