Question

20x ×3-60x×2+45 x =0​

Answer 1

Ответ:

60х-120х+45х=0

105х-120х=0

-15х=0

х=0

ответ:0

Объяснение:

Answer 2

It seems like you've provided a quadratic equation in terms of "x." The equation you've given is:

20x^3 - 60x^2 + 45x = 0

To solve this equation, we can start by factoring out the common factor, which in this case is 5x:

5x(4x^2 - 12x + 9) = 0

Now, we need to solve the quadratic factor, which is:

4x^2 - 12x + 9 = 0

This quadratic equation can be factored further, or we can use the quadratic formula to find its solutions. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In our case, a = 4, b = -12, and c = 9. Plugging these values into the formula:

x = (12 ± √((-12)^2 - 4 * 4 * 9)) / (2 * 4) x = (12 ± √(144 - 144)) / 8 x = (12 ± √0) / 8 x = (12 ± 0) / 8

Since the square root of 0 is 0, both solutions coincide:

x = 12 / 8 x = 3 / 2

So, the solutions for the given equation are x = 0, and x = 3/2.