Question

(x+1)^2+(x-6)^2=2x^2

Answer 1

$(x+1)^2+(x-6)^2=2x^2\\x^2+2x+1+x^2-12x+36=2x^2\\2x^2-10x+37=2x^2\\-10x+37=0\\-10x=-37\;\;\;|:-10\\x=(37/10)-->x=3.7$

Answer 2

Ответ:

(x+1)^2+(x-6)^2=2x^2

х²+2х+1+х²-12х+36=2х²

2х²-10х+37=2х²

-10х+37=0

-10х=-37

х=37\10

х=3,7

Answer 3

To solve the equation (x + 1)^2 + (x - 6)^2 = 2x^2, we can expand the squared terms and simplify:

Expanding the left side: (x + 1)^2 + (x - 6)^2 = (x + 1)(x + 1) + (x - 6)(x - 6) = x^2 + 2x + 1 + x^2 - 12x + 36 = 2x^2 - 10x + 37

Now we have the equation: 2x^2 - 10x + 37 = 2x^2

Subtracting 2x^2 from both sides: -10x + 37 = 0

Now, let's solve for x:

Subtracting 37 from both sides: -10x = -37

Dividing by -10: x = -37 / -10 x = 3.7

So the solution to the equation (x + 1)^2 + (x - 6)^2 = 2x^2 is x = 3.7.