Question

Y-x= -3 _________x-y= -2 2x+y= 9_________x-2y=4

Answer 1

Ответ:

y-x=12

x-y= x+12+11

ответ:24

Объяснение:

Answer 2

It looks like you have a system of linear equations with two equations and two variables in each set. Let's solve each set of equations separately:

Set 1:

1. $Y - X = -3$
2. $X - Y = -2$

For this set of equations, you can add the two equations together to eliminate the $Y$ terms:

Adding equation 1 and equation 2: $(Y - X) + (X - Y) = -3 + (-2)$ $0 = -5$

Since $0 \neq -5$, this system of equations does not have a solution. The two equations are contradictory, and there is no consistent solution that satisfies both equations.

Set 2:

1. $2X + Y = 9$
2. $X - 2Y = 4$

For this set of equations, you can solve for one variable in one equation and substitute it into the other equation:

Solve equation 2 for $X$: $X = 4 + 2Y$

Substitute $X$ into equation 1: $2(4 + 2Y) + Y = 9$ $8 + 4Y + Y = 9$ $5Y = 1$ $Y = \frac{1}{5}$

Now substitute $Y$ back into the equation for $X$: $X = 4 + 2 \left(\frac{1}{5}\right) = \frac{14}{5}$

So, the solution for this set of equations is $X = \frac{14}{5}$ and $Y = \frac{1}{5}$.

In summary:

1. The first set of equations has no solution.
2. The second set of equations has a solution with $X = \frac{14}{5}$ and $Y = \frac{1}{5}$.