Question

5)3x^2-4=0 6)9x^2+8=18x 7)2x=-x^2-1 СРОЧНО ПОЖАЛУЙСТА ПОМОГИТЕ

Answer 1

Ответ:

Объяснение:

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Answer 2

1. To solve the equation 3x^2 - 4 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 3, b = 0, and c = -4. Plugging these values into the quadratic formula, we get:

x = (-0 ± √(0^2 - 4 * 3 * -4)) / (2 * 3) x = (± √(0 + 48)) / 6 x = ± √48 / 6

Simplifying further, we have:

x = ± √8 / √6 x = ± 2√2 / √6 x = ± (2√2 / √6) * (√6 / √6) x = ± 2√12 / 6 x = ± 2√(2 * 2 * 3) / 6 x = ± 4√3 / 6 x = ± 2√3 / 3

Therefore, the solutions to the equation 3x^2 - 4 = 0 are x = 2√3 / 3 and x = -2√3 / 3.

2. To solve the equation 9x^2 + 8 = 18x, we can rearrange it to the standard quadratic form by moving all the terms to one side:

9x^2 - 18x + 8 = 0

Next, we can use the quadratic formula to find the solutions. In this case, a = 9, b = -18, and c = 8. Plugging these values into the quadratic formula, we get:

x = (-(-18) ± √((-18)^2 - 4 * 9 * 8)) / (2 * 9) x = (18 ± √(324 - 288)) / 18 x = (18 ± √36) / 18 x = (18 ± 6) / 18

Simplifying further, we have:

x = (18 + 6) / 18 or x = (18 - 6) / 18 x = 24 / 18 or x = 12 / 18 x = 4 / 3 or x = 2 / 3

Therefore, the solutions to the equation 9x^2 + 8 = 18x are x = 4/3 and x = 2/3.

3. To solve the equation 2x = -x^2 - 1, we can rearrange it to the standard quadratic form by moving all the terms to one side:

x^2 + 2x + 1 = 0

This equation is already in the standard form of a quadratic equation, so we can proceed to find the solutions. In this case, a = 1, b = 2, and c = 1. Plugging these values into the quadratic formula, we get:

x = (-2 ± √(2^2 - 4 * 1 * 1)) / (2 * 1) x = (-2 ± √(4 - 4)) / 2 x = (-2 ± √0) / 2 x = (-2 ± 0) / 2 x = -1

Therefore, the solution to the equation 2x = -x^2 - 1 is x = -1.