Question

2sin29°×cos61° Формула: sin a cos b[sin(a+b)+sin(a-b)

Answer 1

Ответ:

1-sin(32)

Объяснение:

Сначала используя промежуточную формулу преобразовываем выражение.Далее упрощаем выражение используя свойства чет. и нечет. тригонометрических функций. Вычисляем значение используя таблицу и потом сокращаем на 2.

2*0.5*(sin(90)+sin(-32))-промежуточное действие

Answer 2

The given formula is:

2sin(29°) × cos(61°) = sin(a) cos(b) [sin(a+b) + sin(a-b)]

Let's substitute the values of a and b into the formula:

a = 29° b = 61°

sin(a) = sin(29°) cos(b) = cos(61°)

Substituting these values, the formula becomes:

2sin(29°) × cos(61°) = sin(29°) cos(61°) [sin(29° + 61°) + sin(29° - 61°)]

Now, let's simplify the equation further:

sin(29° + 61°) = sin(90°) = 1 (since sin(90°) = 1) sin(29° - 61°) = sin(-32°) = -sin(32°) (since sin(-θ) = -sin(θ))

Plugging in the values, the equation becomes:

2sin(29°) × cos(61°) = sin(29°) cos(61°) [1 + (-sin(32°))]

Simplifying the equation:

2sin(29°) × cos(61°) = sin(29°) cos(61°) - sin(29°) cos(61°)sin(32°)

Therefore, the simplified form of the given expression is:

2sin(29°) × cos(61°) = sin(29°) cos(61°) - sin(29°) cos(61°)sin(32°)