Question

(x-2)²+5x=(x-1)(x+1)

Answer 1

Ответ:

x = − 5

Объяснение:

Answer 2

To solve the equation $(x-2)^2 + 5x = (x-1)(x+1)$, we can start by expanding and simplifying both sides:

$(x-2)^2 + 5x = (x-1)(x+1)$ $x^2 - 4x + 4 + 5x = x^2 - 1$

Now, let's collect like terms and simplify further:

$x^2 - 4x + 4 + 5x = x^2 - 1$ $x^2 + x + 4 = x^2 - 1$

We can eliminate the $x^2$ terms on both sides by subtracting $x^2$ from both sides:

$x^2 + x + 4 - x^2 = x^2 - 1 - x^2$ $x + 4 = -1$

Now, we can isolate the $x$ term by subtracting 4 from both sides:

$x + 4 - 4 = -1 - 4$ $x = -5$

Therefore, the solution to the equation $(x-2)^2 + 5x = (x-1)(x+1)$ is $x = -5$.