Question

(x+4y=-6 < (3x-8y=-2

Answer 1

Ответ:

все на фото

Объяснение:

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Answer 2

It looks like you have a system of linear inequalities with two equations involving variables x and y:

1. $x + 4y < -6$
2. $3x - 8y < -2$

To solve this system, you can follow these steps:

Step 1: Solve each inequality for y:

1. $y < \frac{-x - 6}{4}$
2. $y > \frac{3x + 2}{8}$

Step 2: Graph each inequality on a coordinate plane: Graph the first inequality:

• Since $y < \frac{-x - 6}{4}$, you'll draw a dashed line with a slope of -1/4 passing through the point (-6, 0), and shade the region below the line.

Graph the second inequality:

• Since $y > \frac{3x + 2}{8}$, you'll draw a dashed line with a slope of 3/8 passing through the point (-2, 0), and shade the region above the line.

Step 3: The solution to the system is the region where the shaded areas of both inequalities overlap.

Please note that I cannot draw graphs directly here, but you can follow the steps outlined above to graph the inequalities on a piece of paper or using graphing software. The solution will be the region where the shaded areas of both inequalities overlap. This region represents the values of x and y that satisfy both inequalities simultaneously.