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Реши систему уравнений методом подстановки: {x−2y=−77x−4y=7 Смотреть ответ Пеппер Пеппер Ответ: (4,2;  5,6) Объяснение: {x−2y=−7;  х=2у-7 7x−4y=7 х=2у-7 7(2у-7)-4у=7 х=2у-7 14у-49-4у=7 х=2у-7 10у=56 у=5,6 х=2*5,6-7=4,2 клименко лох Новые вопросы в Алгебра Знайдіть область значень функції у = -х² + 2x + 7. ​ Найдите площадь криволинейной трапеции ограниченной линиями: у=х2-4х+7 , у=0 , х=0 , х=1​ найти первообразную функции f(x)=x^3-4x-3​ найти первообразную f(x)=5x^3-4sin(3x)​ помогите. почему тут из sin(- π - 2π/3) получается sin (- 5π/6)??? Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Давайте рассмотрим систему уравнений и решим ее методом подстановки:

Система уравнений:

1. $x - 2y = -7$
2. $7x - 4y = 7$

Исходя из первого уравнения, можно выразить $x$ через $y$: $x = 2y - 7$

Подставим это значение $x$ во второе уравнение: $7(2y - 7) - 4y = 7$

Упростим уравнение: $14y - 49 - 4y = 7$ $10y = 56$ $y = 5.6$

Теперь, когда мы нашли $y$, можем найти $x$ с использованием первого уравнения: $x = 2y - 7 = 2 \cdot 5.6 - 7 = 4.2$

Таким образом, решение системы уравнений составляет $x = 4.2$ и $y = 5.6$.

Теперь перейдем к вашим дополнительным вопросам:

1. Область значений функции $y = -x^2 + 2x + 7$ - это множество всех возможных значений, которые может принимать функция при изменении переменной $x$. Для данной квадратичной функции, так как коэффициент при квадрате отрицателен, она открывается вниз, и её вершина будет наивысшей точкой в области значений. Следовательно, область значений будет вся действительная ось $y$, начиная от вершины функции и уходя вниз.

2. Для нахождения площади криволинейной трапеции ограниченной кривыми $y = x^2 - 4x + 7$, $y = 0$, $x = 0$ и $x = 1$, вам потребуется интегрирование. Площадь можно вычислить как разность интегралов этих функций в заданных пределах.

3. Первообразная функции $f(x) = x^3 - 4x - 3$ будет $F(x) = \frac{1}{4}x^4 - 2x^2 - 3x + C$, где $C$ - произвольная постоянная.

4. Первообразная функции $f(x) = 5x^3 - 4\sin(3x)$ может быть найдена с помощью методов интегрирования. Это будет сложное задание, требующее применения правил интегрирования.

5. Ответ на ваш вопрос о $\sin(-\pi - \frac{2\pi}{3})$ - это $\sin(-\frac{5\pi}{6})$, потому что $-\pi - \frac{2\pi}{3} = -\frac{5\pi}{3}$, а затем при переводе из радианов в обычные градусы $-\frac{5\pi}{3}$ равно $-300^\circ$, что эквивалентно $60^\circ$. Таким образом, $\sin(-\pi - \frac{2\pi}{3}) = \sin(-\frac{5\pi}{6})$.