Question

Log1/5 (4x-6) = log1/5x=?​

Answer 1

Ответ:

2

Объяснение:

Найдем ОДЗ: 4х-6 >0 и х > 0

x > 1.5, x > 0 Из большего выбираем большее, значит ОДЗ: x > 1.5

Снимаем логарифмы и получаем

4х-6=х

3х=6

х=2

Answer 2

To solve the equation log₁/₅(4x - 6) = log₁/₅x for x, we can use properties of logarithms.

First, remember the logarithmic identity: logₐb = logₐc if and only if b = c.

In your equation, both sides have the same base (1/5), so we can set the expressions inside the logarithms equal to each other:

4x - 6 = x

Now, let's solve for x:

Subtract x from both sides:

4x - x = 6 3x = 6

Divide both sides by 3:

x = 2

So, the solution to the equation log₁/₅(4x - 6) = log₁/₅x is x = 2.