Question

A) 9-8х=-6+1 б) 7(3х-1)=-4х+23 х+25 3 в) —— = — х+10 2

Answer 1

Ответ:

А) 9+6-1=8х

14=8х

14-8=х

6=х

х=-6

Answer 2

Sure, I can help you solve these equations step by step:

A) $9 - 8x = -6 + 1$

Let's start by simplifying both sides of the equation:

$9 - 8x = -5$

Now, let's isolate $x$ by subtracting 9 from both sides:

$-8x = -5 - 9$

$-8x = -14$

Finally, divide both sides by -8 to solve for $x$:

$x = \frac{-14}{-8}$

$x = \frac{7}{4}$

So, the solution for equation A is $x = \frac{7}{4}$.

B) $7(3x - 1) = -4x + 23 + x + 25$

First, distribute the 7 on the left side of the equation:

$21x - 7 = -4x + 23 + x + 25$

Combine the $x$ terms on the right side:

$21x - 7 = -3x + 48$

Add $3x$ to both sides:

$21x + 3x - 7 = 48$

$24x - 7 = 48$

Now, add 7 to both sides:

$24x = 55$

Finally, divide both sides by 24 to solve for $x$:

$x = \frac{55}{24}$

So, the solution for equation B is $x = \frac{55}{24}$.

C) $\frac{x + 25}{3} = \frac{2}{x + 10}$

To eliminate fractions, let's cross-multiply:

$(x + 25)(x + 10) = 2(3)$

Expand the left side:

$x^2 + 35x + 10x + 250 = 6$

Combine the $x$ terms:

$x^2 + 45x + 250 = 6$

Subtract 6 from both sides:

$x^2 + 45x + 244 = 0$

This quadratic equation doesn't factor easily, so you might need to use the quadratic formula:

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where the equation is in the form $ax^2 + bx + c = 0$.

In this case, $a = 1$, $b = 45$, and $c = 244$. Plugging these values into the formula:

$x = \frac{-45 \pm \sqrt{45^2 - 4 \cdot 1 \cdot 244}}{2 \cdot 1}$

Calculate the discriminant under the square root:

$x = \frac{-45 \pm \sqrt{2025 - 976}}{2}$

$x = \frac{-45 \pm \sqrt{1049}}{2}$

The solutions are then:

$x = \frac{-45 + \sqrt{1049}}{2}$ and $x = \frac{-45 - \sqrt{1049}}{2}$

These are the exact solutions for equation C.