Question

1) 4x-y=5 3x+2y=12 2)5x+4y=13 3x+5y=13

Answer 1

Ответ:

4x-y-5=0

3x+2y-12=0

5x+4y-13=0

3x+5y-13=0

Объяснение:

4x-y=5

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4x-y-5=5-5

также с другими:)

Answer 2

To solve the given system of equations, you can use either the substitution method or the elimination method. I will demonstrate how to solve both systems of equations.

1. Using the substitution method: Let's solve the first system of equations:

4x - y = 5 ---(1) 3x + 2y = 12 ---(2)

From equation (1), we can express y in terms of x: y = 4x - 5

Substitute this value of y in equation (2):

3x + 2(4x - 5) = 12 3x + 8x - 10 = 12 11x = 22 x = 2

Now substitute the value of x back into equation (1) to solve for y:

4(2) - y = 5 8 - y = 5 y = 8 - 5 y = 3

So the solution to the first system of equations is x = 2 and y = 3.

2. Using the elimination method: Let's solve the second system of equations:

5x + 4y = 13 ---(3) 3x + 5y = 13 ---(4)

To eliminate one variable, we can multiply equation (3) by 3 and equation (4) by 5:

15x + 12y = 39 ---(5) 15x + 25y = 65 ---(6)

Now, subtract equation (5) from equation (6) to eliminate x:

(15x + 25y) - (15x + 12y) = 65 - 39 15x - 15x + 25y - 12y = 26 13y = 26 y = 26/13 y = 2

Substitute the value of y back into equation (3) to solve for x:

5x + 4(2) = 13 5x + 8 = 13 5x = 13 - 8 5x = 5 x = 5/5 x = 1

Therefore, the solution to the second system of equations is x = 1 and y = 2.