Question

(2-с)^2-с(с-4)=. с=-1/8​

Answer 1

Ответ:

4

Объяснение:

$></p> <p>Так как все 4с и с^2 взаимно уничтожаются, то остается только число, равное 4 </p> </div> <div class=$ 0 0

Answer 2

Let's solve the equation step by step:

(2 - c)^2 - c(c - 4) = 0

First, expand the square:

(2 - c)(2 - c) - c(c - 4) = 0

Now, use the distributive property to multiply the terms:

(4 - 4c + c^2) - (c^2 - 4c) = 0

Now, simplify the equation by canceling out like terms:

4 - 4c + c^2 - c^2 + 4c = 0

Notice that the -4c and +4c terms cancel out:

4 - 0 = 0

So, we have:

4 = 0

This is not a valid equation. Therefore, there is no solution for c that satisfies this equation. The initial equation does not have a solution when c is set to -1/8.