Question

A train increases its speed steadily from 10 m/s to 20 m/s in 1minute. what is its average speed during this time, in m/s?​

Answer 1

Ответ:

Все просто.

Вопрос

930 метров.

Решение

Здесь скорость неуклонно растет.

так за 1 минуту скорость увеличивается в 10 раз. Таким образом, скорость увеличивается на 1 м / с каждые 6 секунд.

so,

6 × 11 = 66

6× 12 = 72

6 × 13 = 78

6 × 14 = 84

6 × 15 = 90

6 × 16 = 96

6 × 17 = 102

6 × 18 = 108

6 × 19 = 114

6 × 20 = 120

Total = 960.

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Answer 2

To calculate the average speed of the train during this time interval, you can use the formula for average speed:

Average Speed = Total Distance / Total Time

In this case, the train's speed increases from 10 m/s to 20 m/s in 1 minute. However, the average speed is not simply the arithmetic mean of the initial and final speeds because the train's speed is increasing steadily. Instead, we need to consider the distance covered at each speed.

Let's calculate the distance covered during this time interval:

Initial speed = 10 m/s Final speed = 20 m/s Time = 1 minute = 60 seconds

Average speed = Total Distance / Total Time

Distance covered at initial speed = Initial speed * Time Distance covered at final speed = Final speed * Time

Total Distance = Distance covered at initial speed + Distance covered at final speed Total Time = Time

Total Distance = (10 m/s * 60 s) + (20 m/s * 60 s) = 600 m + 1200 m = 1800 m Total Time = 60 s

Average Speed = Total Distance / Total Time Average Speed = 1800 m / 60 s = 30 m/s

So, the average speed of the train during this time interval is 30 m/s.