Question

(х+5)-3=10(2х+7)(3х-9)*(2-4х)=0​

Answer 1

Ответ:

1)

(х+5)-3=10

х +5 =10+3

х+5=13

х=13-5

х=8

Ответ: х=8

2)

(2х+7)(3х-9)*(2-4х)=0

2х+7=0

2х=-7

х=-7/2=-3,5

3х-9=0

3х=9

х=9/3

х=3

(2-4х)=0

-4х=-2

х=2/4=1/2=0,5

Ответ: уравнение имеет три корня  х=-3,5; х=3; х=0,5

Объяснение:

уравнение равно нулю если один из множителей равен нулю

Answer 2

Ответ:

Объяснение:

(х+5)-3=10

х+5=10+3

х = 13 - 5

х = 8

(2х+7)(3х-9)*(2-4х)=0​

2х+7 = 0     или  3х-9 = 0        или  2-4х =0​

2х = -7                 3х = 9                    -4х = -2

х = -7/2                  х = 9/3                    х = -2/-4 = 1/2

х(1) = - 3,5                х(2) = 3                 х(3) = 0,5

Answer 3

It seems like you've provided a system of equations. Let's solve it step by step:

1. First Equation: $x + 5 - 3 = 0$ Simplify the equation: $x + 2 = 0$ Subtract 2 from both sides: $x = -2$

2. Second Equation: $10(2x + 7)(3x - 9)(2 - 4x) = 0$ This equation is a product of terms, and it will be equal to zero if any of these terms is equal to zero. So, we need to solve for $x$ in each term separately.

   a. $2x + 7 = 0$ Subtract 7 from both sides: $2x = -7$ Divide by 2: $x = -\frac{7}{2}$

   b. $3x - 9 = 0$ Add 9 to both sides: $3x = 9$ Divide by 3: $x = 3$

   c. $2 - 4x = 0$ Subtract 2 from both sides: $-4x = -2$ Divide by -4: $x = \frac{1}{2}$

So, the solutions for the second equation are $x = -\frac{7}{2}$, $x = 3$, and $x = \frac{1}{2}$.

In summary, the solutions for the system of equations are $x = -2$, $x = -\frac{7}{2}$, $x = 3$, and $x = \frac{1}{2}$.