Question

(2h-1)•(3-h)•(h+5)=...h*3-...h*2+...h-...

Answer 1

Ответ:

-2; -3; 32; -15 - пропуски - слева - на - право

Объяснение:

= -(2h - 1)(h - 3)(h + 5) = -(2h - 1)(h² + 2h - 15) = -(2h³ + 4h² - 30h - h² - 2h + 15) = -2h³ -3h² + 32h - 15

Answer 2

Let's expand the given expression step by step:

(2h - 1) • (3 - h) • (h + 5)

First, let's multiply the first two factors using the distributive property:

(2h - 1) • (3 - h) = 2h • 3 - 2h • h - 1 • 3 + 1 • h = 6h - 2h^2 - 3 + h

Now, let's multiply the result above by the third factor:

(6h - 2h^2 - 3 + h) • (h + 5) = 6h • h + 6h • 5 - 2h^2 • h - 2h^2 • 5 - 3 • h - 3 • 5 + h • h + h • 5

Simplify each term:

6h^2 + 30h - 2h^3 - 10h^2 - 3h - 15 + h^2 + 5h

Now, combine like terms:

-2h^3 + (6h^2 - 10h^2 + h^2) + (30h + 5h - 3h) + (-15) -2h^3 - 3h^2 + 32h - 15

So, the expanded expression is -2h^3 - 3h^2 + 32h - 15.