Question

3) z+ 2,8z- 2,2> (9-2-z)(1,2- z) +0,2z+11,5​

Answer 1

Объяснение: Решение и ответ в прикреплённом файле

Answer 2

It seems like you've provided an inequality that involves variables. The given inequality is:

$3z + 2.8z - 2.2 > (9 - 2 - z)(1.2 - z) + 0.2z + 11.5$

Let's simplify and solve this inequality step by step:

1. Combine the terms on the left side: $5.8z - 2.2 > (7 - z)(1.2 - z) + 0.2z + 11.5$

2. Expand the terms on the right side: $5.8z - 2.2 > 8.4 - 7z - z^2 + 0.2z + 11.5$

3. Combine like terms: $5.8z - 2.2 > 19.9 - 6.8z - z^2$

4. Rearrange the terms to get the quadratic equation on one side: $z^2 + 12.6z - 22.1 < 0$

5. This is a quadratic inequality. To solve it, we need to find the values of $z$ for which the inequality is true. You can use various methods to solve quadratic inequalities, such as factoring or the quadratic formula. In this case, let's use the quadratic formula:

   The quadratic formula is given by: $z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

   For the inequality $z^2 + 12.6z - 22.1 < 0$, the coefficients are $a = 1$, $b = 12.6$, and $c = -22.1$.

   Plugging these values into the quadratic formula: $z = \frac{-12.6 \pm \sqrt{12.6^2 - 4 \cdot 1 \cdot (-22.1)}}{2 \cdot 1}$

6. Calculate the discriminant inside the square root: $\text{Discriminant} = 12.6^2 - 4 \cdot 1 \cdot (-22.1) = 271.16$

7. Since the discriminant is positive, there are two distinct real roots: $z = \frac{-12.6 + \sqrt{271.16}}{2} \approx 1.52$ $z = \frac{-12.6 - \sqrt{271.16}}{2} \approx -14.12$

8. Now we need to determine the intervals where the inequality is satisfied. Since the coefficient of the $z^2$ term is positive, the parabola opens upwards. The values of $z$ that satisfy the inequality are those within the range $-14.12 < z < 1.52$.

So, the solution to the inequality $3z + 2.8z - 2.2 > (9 - 2 - z)(1.2 - z) + 0.2z + 11.5$ is $-14.12 < z < 1.52$.