Question

7-3y*4+2y-4 при y=5 66a:2-32a+(1-a) при a=4 (3m-2)*2-6*(3n-n+1) при m=1 n=0

Answer 1

Ответ:

1)-47

2)1

3)-16

Объяснение:

7-3y*4+2y-4=7-15×4+10-4=7-60+10-4=-53+10-4=-43-4=-47

66a:2-32a+(1-a)=264:2-128-3=132-128-3=4-3=1

(3m-2)*2-6*(3n-n+1)=(3-2)×2-6×(3-1+1)=1×2-6×3=2-18=-16

Если не сложно сделайте этот ответ лучшим

Answer 2

To evaluate the given expressions, let's substitute the given values for the variables and simplify the expressions:

1. Expression: 7 - 3y * 4 + 2y - 4, where y = 5

Substituting y = 5: 7 - 3 * 5 * 4 + 2 * 5 - 4

Performing the operations: 7 - 60 + 10 - 4 -53

Therefore, when y = 5, the expression 7 - 3y * 4 + 2y - 4 is equal to -53.

2. Expression: 66a:2 - 32a + (1 - a), where a = 4

Substituting a = 4: 66 * 4 / 2 - 32 * 4 + (1 - 4)

Performing the operations: 264 / 2 - 128 - 3 132 - 128 - 3 4 - 3 1

Therefore, when a = 4, the expression 66a:2 - 32a + (1 - a) is equal to 1.

3. Expression: (3m - 2) * 2 - 6 * (3n - n + 1), where m = 1 and n = 0

Substituting m = 1 and n = 0: (3 * 1 - 2) * 2 - 6 * (3 * 0 - 0 + 1)

Performing the operations: (3 - 2) * 2 - 6 * (0 - 0 + 1) 1 * 2 - 6 * (0 + 1) 2 - 6 * 1 2 - 6 -4

Therefore, when m = 1 and n = 0, the expression (3m - 2) * 2 - 6 * (3n - n + 1) is equal to -4.