Question

1) (x-a)(x-b)(x-c) 2) 3y(2x-1)-5x(1-y)

Answer 1

Объяснение:

Если что делала не я а приложение, надеюсь тебе это поможет))

Answer 2

It looks like you've provided two algebraic expressions. Let me help you understand and work with them.

Expression 1: (x - a)(x - b)(x - c)

This is a product of three binomials, each in the form of (x - constant). It can also be expanded to get a polynomial expression. The expansion would involve multiplying out all the terms:

(x - a)(x - b)(x - c) = x^3 - (a + b + c)x^2 + (ab + ac + bc)x - abc

Here's what each term expansion looks like:

• First term: x * x * x = x^3
• Second term: -a * x * x = -ax^2
• Third term: -b * x * x = -bx^2
• Fourth term: -c * x * x = -cx^2
• Fifth term: a * b * x = abx
• Sixth term: a * c * x = acx
• Seventh term: b * c * x = bcx
• Eighth term: -a * b * c = -abc

Expression 2: 3y(2x - 1) - 5x(1 - y)

This expression involves multiplication and subtraction of terms. Let's simplify it step by step:

1. Distribute the terms within the parentheses: 3y * 2x - 3y * 1 - 5x * 1 + 5x * y

2. Multiply the terms: 6xy - 3y - 5x + 5xy

3. Combine like terms: 11xy - 3y - 5x

So, the simplified expression is: 11xy - 3y - 5x

If you have any further questions or need additional assistance, feel free to ask!