Question

Arccos(-√2/2)-arcsin (-1)=​

Answer 1

Ответ:

arccos(-√2/2) - arcsin(-1)=π- arccos√2/2+π/2=π-π/4+π/2=3π/2-π/4=5π/4.

Answer 2

Let's break down the calculation step by step:

1. First, let's find the value of $\arccos(-\sqrt{2}/2)$: $\arccos(-\sqrt{2}/2)$ represents the angle whose cosine is $-\sqrt{2}/2$. This angle corresponds to $3\pi/4$ radians or $135^\circ$.

2. Next, let's find the value of $\arcsin(-1)$: $\arcsin(-1)$ represents the angle whose sine is $-1$. This angle corresponds to $-\pi/2$ radians or $-90^\circ$.

Now, let's calculate the expression: $\arccos(-\sqrt{2}/2) - \arcsin(-1) = (3\pi/4) - (-\pi/2) = 3\pi/4 + \pi/2 = 5\pi/4$

So, $\arccos(-\sqrt{2}/2) - \arcsin(-1) = 5\pi/4$ radians.