Question

3у-квадрат-8у+4=0а=3,в=-8,с=4​

Answer 1

Ответ:

x1=2

x2=2/3

Объяснение:

3y²-8y+4=0

D=(-8)²-4×3×4=64-48=16

x1=8+4/6=2 x2=8-4/6=2/3

Answer 2

To solve the equation 3у² - 8у + 4 = 0 with the given values of a = 3, b = -8, and c = 4, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the given values into the quadratic formula, we have:

у = (-(-8) ± √((-8)² - 4 * 3 * 4)) / (2 * 3)

Simplifying further:

у = (8 ± √(64 - 48)) / 6 у = (8 ± √16) / 6 у = (8 ± 4) / 6

Now, we can calculate the two possible values of у:

у₁ = (8 + 4) / 6 = 12 / 6 = 2 у₂ = (8 - 4) / 6 = 4 / 6 = 2/3

Therefore, the solutions to the equation 3у² - 8у + 4 = 0 are у = 2 and у = 2/3.