Question

2)x = 2-y,y2 + x = 32;​

Answer 1

Ответ:

у=30

Объяснение:

2у+2-у=32

2у-у=32-2

у=30

Answer 2

It seems like you've provided a system of two equations with two variables. The equations are:

1. $2x = 2 - y$
2. $y^2 + x = 32$

To solve this system of equations, we can substitute the value of $2x$ from the first equation into the second equation:

Substitute $2x = 2 - y$ into $y^2 + x = 32$:

$y^2 + (2 - y) = 32$

Now, expand the equation:

$y^2 + 2 - y = 32$

Combine like terms:

$y^2 - y + 2 = 32$

Subtract 2 from both sides:

$y^2 - y = 30$

Now, we have a quadratic equation in terms of $y$. We can solve for $y$ using factoring, completing the square, or the quadratic formula. However, this equation seems a bit complex to factor easily, so I'll proceed with the quadratic formula:

The quadratic formula states that for an equation $ax^2 + bx + c = 0$, the solutions for $x$ are given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In our case, $a = 1$, $b = -1$, and $c = 30$:

$y = \frac{1 \pm \sqrt{(-1)^2 - 4 \cdot 1 \cdot 30}}{2 \cdot 1}$

Simplify under the square root:

$y = \frac{1 \pm \sqrt{1 - 120}}{2}$

Since the value under the square root is negative, we end up with complex solutions. These solutions involve the imaginary unit $i$:

$y = \frac{1 \pm \sqrt{-119}}{2} = \frac{1 \pm i\sqrt{119}}{2}$

So, the solutions for $y$ are complex numbers. If you need further assistance or clarification, feel free to ask!