Question

2x3y2-y3x2=36 2x2y-y2x=6

Answer 1

hibö0ho oh pphph o p p k

Объяснение:

nnnn

Answer 2

Ответ:

{ 2x³y² -x²y³ =36 ; 2x²y -xy² =6 .⇔{ (xy)²(2x -y) =36 ;xy(2x -y) =6.

Разделим первое уравнение системы на второе получим xy =6 и новую систему :

{ xy = 6 ; xy(2x -y) = 6.⇔{ xy = 6 ; 6(2x -y) = 6.⇔{ xy = 6 ; 2x -y =1 .

{ xy = 6 ; y =2x -1.

x(2x -1) =6 ;

2x² - x -6 =0 ;

D =1 -4*2*(-6) =49 =7² ⇒√D =7 ;

x₁ =(1-7)/2*2 = -3/2.

x₂ =(1+7)/4 =2.

Answer 3

To solve this system of equations:

1. 2x^3y^2 - y^3x^2 = 36
2. 2x^2y - y^2x = 6

You can start by simplifying the equations:

From equation (2), you can factor out x and y:

2xy(x - y) = 6

Now, let's solve equation (2) for x:

x = 3/y(x - y)

Now, substitute this expression for x into equation (1):

2(3/y)(x - y)^3y^2 - y^3(3/y)(x - y)^2 = 36

Now, simplify further:

2(3/y)(x - y)^3y^2 - 3y(x - y)^2 = 36

Next, divide both sides by 3:

2(x - y)^3y^2 - y(x - y)^2 = 12

Now, let's substitute the expression we found for x back into this equation:

2[(3/y)(x - y)]^3y^2 - y[(3/y)(x - y)]^2 = 12

Now, simplify further:

2(3(x - y))^3y^2 - y(3(x - y))^2 = 12

Now, let's simplify the equation even further:

2(27x^3 - 54x^2y + 27xy^2) - 9(x^2 - 2xy + y^2) = 12

Now, distribute and simplify:

54x^3 - 108x^2y + 54xy^2 - 9x^2 + 18xy - 9y^2 = 12

Now, combine like terms:

54x^3 - 108x^2y + 54xy^2 - 9x^2 + 18xy - 9y^2 - 12 = 0

Now, you have a single equation in terms of x and y. Unfortunately, this equation is quite complex and doesn't seem to have simple solutions. You might need to use numerical methods or software to find approximate solutions for x and y.