Question

2*(x^2) - (5 - i)x + 6 = 0

Answer 1

Ответ:

46,это ответ кто не верит я проверила

Answer 2

To solve the quadratic equation $2x^2 - (5 - i)x + 6 = 0$, you can use the quadratic formula, which is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a = 2$, $b = -(5 - i)$, and $c = 6$. Now, plug these values into the quadratic formula:

$x = \frac{-(5 - i) \pm \sqrt{(-5 + i)^2 - 4(2)(6)}}{2(2)}$

First, simplify the expression under the square root:

$(5 - i)^2 = 25 - 10i + i^2 = 25 - 10i - 1 = 24 - 10i$

Now, plug this value back into the quadratic formula:

$x = \frac{-(5 - i) \pm \sqrt{24 - 10i - 4(2)(6)}}{4}$

$x = \frac{-5 + i \pm \sqrt{24 - 48 - 10i}}{4}$

$x = \frac{-5 + i \pm \sqrt{-24 - 10i}}{4}$

Now, you can simplify the square root of a complex number by writing it in the form $a + bi$, where $a$ and $b$ are real numbers:

$\sqrt{-24 - 10i} = \sqrt{-1} \cdot \sqrt{24 + 10i} = i\sqrt{24 + 10i}$

So, the equation becomes:

$x = \frac{-5 + i \pm i\sqrt{24 + 10i}}{4}$

Now, you have two possible solutions:

1. $x = \frac{-5 + i + i\sqrt{24 + 10i}}{4}$
2. $x = \frac{-5 + i - i\sqrt{24 + 10i}}{4}$

These are your solutions to the quadratic equation. You can simplify them further if needed, but they are already in a suitable form.