Question

(p2−p+5)⋅(14p2+p−5).

Answer 1

Ответ:

21p⁴-20p³+99p²+10p-25

Объяснение:

(p²-p+5)(21p²+p-5)=21p⁴+p³-5p²-21p³-p²+5p+105p²+5p-25=21p⁴-20p³+99p²+10p-25

Answer 2

Ответ:

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Answer 3

To multiply the expressions (p^2 - p + 5) and (14p^2 + p - 5), you can use the distributive property, which states that for any real numbers a, b, and c:

(a + b) * c = a * c + b * c

In this case, you have:

(p^2 - p + 5) * (14p^2 + p - 5)

Let's distribute each term in the first expression to the second expression:

(p^2 * 14p^2) + (p^2 * p) - (p^2 * 5) + (-p * 14p^2) + (-p * p) - (-p * 5) + (5 * 14p^2) + (5 * p) - (5 * 5)

Now, simplify each term:

14p^4 + p^3 - 5p^2 - 14p^3 - p^2 + 5p + 70p^2 + 5p - 25

Next, combine like terms:

(14p^4 - 14p^3) + (p^3 - p^3) + (-5p^2 + 70p^2 - p^2) + (5p + 5p) - 25

Simplify further:

14p^4 - 13p^3 + 64p^2 + 10p - 25

So, the product of (p^2 - p + 5) and (14p^2 + p - 5) is:

14p^4 - 13p^3 + 64p^2 + 10p - 25