
(2x-1)^2-6(6-x)=2x (x+2)(x-3)-(x-5)(5x+5)=x^2-x


Ответы на вопрос

Ответ:
(2х-1)^2-6(6-х)=2х
2х^2-4х+1-36+6х=2х
4х^2-35=0
х^2=35/4
(х+2)(х-3)-(х-5)(5х+5)=х^2-х
х^2-3х+2х-6-(5х^2-20х-25)=х^2-х
-3х+2х-6-5х^2+20х+25=-х
19х+19-5х^2=-х
5х^2-20х-19=0



Let's solve each of these equations step by step:
- (2x - 1)^2 - 6(6 - x) = 2x
Expand the left side of the equation:
(2x - 1)^2 = (2x - 1)(2x - 1) = 4x^2 - 4x + 1
Now, distribute the -6 on the right side of the equation:
-6(6 - x) = -6(6) + 6x = -36 + 6x
So, the equation becomes:
4x^2 - 4x + 1 - 36 + 6x = 2x
Now, combine like terms on the left side:
4x^2 + 2x - 35 = 2x
Subtract 2x from both sides:
4x^2 - 35 = 0
Now, add 35 to both sides:
4x^2 = 35
Divide both sides by 4:
x^2 = 35/4
Take the square root of both sides:
x = ±√(35/4)
x = ±(√35/2)
So, the solutions to the first equation are:
x = √(35/2) and x = -√(35/2)
- (x+2)(x-3) - (x-5)(5x+5) = x^2 - x
Expand both sides of the equation:
(x+2)(x-3) - (x-5)(5x+5) = x^2 - x
(x^2 - 3x + 2x - 6) - (5x^2 - 5x - 25x + 25) = x^2 - x
Now, simplify both sides by combining like terms:
(x^2 - x - 6) - (5x^2 - 30x + 25) = x^2 - x
Now, distribute the negative sign on the left side:
x^2 - x - 6 - 5x^2 + 30x - 25 = x^2 - x
Combine like terms:
(-4x^2 + 29x - 31) = x^2 - x
Now, move all terms to one side of the equation:
-4x^2 + 29x - 31 - x^2 + x = 0
Combine like terms again:
-5x^2 + 30x - 31 = 0
Divide the entire equation by -1 to simplify:
5x^2 - 30x + 31 = 0
This is a quadratic equation. You can use the quadratic formula to find its solutions:
x = (-b ± √(b² - 4ac)) / (2a)
In this case, a = 5, b = -30, and c = 31. Plug these values into the quadratic formula:
x = (-(-30) ± √((-30)² - 4 * 5 * 31)) / (2 * 5)
x = (30 ± √(900 - 620)) / 10
x = (30 ± √280) / 10
x = (30 ± 2√70) / 10
Now, simplify:
x = (3 ± √70)/1
So, the solutions to the second equation are:
x = 3 + √70 and x = 3 - √70


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