Question

4. 6x - 6(2x + 5) = 4(5x - 1) 5. 11 - 4(3x - 1) - 5(4x - 3) = 3x 6. 8(x - 3) + 1 = - 6(2x + 3) - 2x

Answer 1

Ответ:

Смотри решение

Объяснение:

1) Решаем 1 уравнение:

$6x-6(2x+5)=4(5x-1)\\6x-6*2x-6*5=4*5x-4\\6x-12x-30=20x-4\\-6x-30=20x-4\\-6x-20x=-4+30\\-26x=26\\x=\frac{26}{-26}\\x=-\frac{26}{26} \\x=-1$

2) Решаем 2 уравнение:

$11-4(3x-1)-5(4x-3)=3x\\11-4*3x+4-5*4x+15=3x\\11-12x+4-20x+15=3x\\-12x-20x-3x=-11-4-15\\-35x=-30\\x=\frac{-30}{-35}\\x=\frac{30}{35}\\x=\frac{6}{7}$

3) Решаем 3 уравнение:

$8(x-3)+1=-6(2x+3)-2x\\8x-24+1=-12x-18-2x\\8x-23=-14x-18\\8x+14x=-18+23\\22x=5\\x=\frac{5}{22}$

Answer 2

Let's solve each of these equations step by step:

4. $6x - 6(2x + 5) = 4(5x - 1)$

First, distribute the numbers inside the parentheses:

$6x - 12x - 30 = 20x - 4$

Now, combine like terms on both sides of the equation:

$-6x - 30 = 20x - 4$

Next, move all the x terms to one side by adding 6x to both sides:

$-30 = 26x - 4$

Now, add 4 to both sides:

$-26 = 26x$

Finally, divide both sides by 26 to isolate x:

$x = \frac{-26}{26}$

Simplify:

$x = -1$

So, the solution to equation 4 is $x = -1$.

5. $11 - 4(3x - 1) - 5(4x - 3) = 3x$

First, distribute the numbers inside the parentheses:

$11 - 12x + 4 - 20x + 15 = 3x$

Now, combine like terms on both sides of the equation:

$11 + 4 + 15 = 12x + 20x + 3x$

$30 = 35x$

Now, divide both sides by 35 to isolate x:

$x = \frac{30}{35}$

Simplify the fraction:

$x = \frac{6}{7}$

So, the solution to equation 5 is $x = \frac{6}{7}$.

6. $8(x - 3) + 1 = - 6(2x + 3) - 2x$

First, distribute the numbers inside the parentheses:

$8x - 24 + 1 = -12x - 18 - 2x$

Now, combine like terms on both sides of the equation:

$8x - 23 = -14x - 18$

Next, move all the x terms to one side by adding 14x to both sides:

$8x + 14x - 23 = -18$

Combine like terms:

$22x - 23 = -18$

Now, add 23 to both sides:

$22x = 5$

Finally, divide both sides by 22 to isolate x:

$x = \frac{5}{22}$

So, the solution to equation 6 is $x = \frac{5}{22}$.