Question

(3а ^8-14а ^6 +3а^3) :(-а^3)-3а^7 :(-а) ^2 ПРИ а=2​

Answer 1

Ответ:

(3*2 ^8-14*2 ^6 +3*2^3) :(-2^3)-3*2^7 :(-2) ^2=((3*2⁵-14*2³+3)*2³)÷(-2³)-3*2⁷÷2²=((3*32-14*8+3)*8)÷(-2³)-3*2⁵=((96-112+3)*8)÷(-2³)-3*32=(-13*8)÷(-2³)-96=(-104)÷(-2³)-96=104÷8-96=13-96=-83

Answer 2

To solve this expression for the given value of "a," which is a = 2, follow these steps:

1. Substitute the value of "a" into the expression:

   (3a^8 - 14a^6 + 3a^3) / (-a^3) - 3a^7 / (-a)^2

   Now, replace "a" with 2:

   (3(2^8) - 14(2^6) + 3(2^3)) / (-(2^3)) - (3(2^7)) / (-(2)^2)

2. Calculate the values inside the parentheses and exponents:

   (3(256) - 14(64) + 3(8)) / (-8) - (3(128)) / 4

3. Calculate the multiplications:

   (768 - 896 + 24) / (-8) - (384) / 4

4. Perform the additions and subtractions:

   (-104) / (-8) - (384) / 4

5. Simplify further:

   13 + (-96)

6. Finally, add the two results:

   13 - 96 = -83

So, when a = 2, the expression evaluates to -83.