Question

( y-4)(y +6)(4а+1)(2а-3)​

Answer 1

Объяснение:

$(y - 4)(y + 6) = {y}^{2} + 6y - 4y - 24 = {y}^{2} + 2y - 24$

$(4a + 1)(2a - 3) = 8 {a}^{2} - 12a + 2a - 3 = 8 {a}^{2} - 10a - 3$

Answer 2

To expand the given expression, you can use the distributive property to multiply the factors together. Here's how you can expand it step by step:

(1) First, multiply the first two factors (y - 4)(y + 6):

(y - 4)(y + 6) = y(y) + y(6) - 4(y) - 4(6) = y^2 + 6y - 4y - 24 = y^2 + 2y - 24

(2) Now, multiply the next two factors (4a + 1)(2a - 3):

(4a + 1)(2a - 3) = (4a)(2a) + (4a)(-3) + (1)(2a) + (1)(-3) = 8a^2 - 12a + 2a - 3 = 8a^2 - 10a - 3

(3) Finally, multiply the results from step 1 and step 2 together:

(y^2 + 2y - 24)(8a^2 - 10a - 3)

Now, you can use the distributive property to multiply these two expressions together. Multiply each term in the first expression by each term in the second expression:

(y^2)(8a^2) + (y^2)(-10a) + (y^2)(-3) + (2y)(8a^2) + (2y)(-10a) + (2y)(-3) - (24)(8a^2) - (24)(-10a) - (24)(-3)

Now, simplify each term:

8a^2y^2 - 10ay^2 - 3y^2 + 16a^2y - 20ay - 6y - 192a^2 + 240a + 72

So, the fully expanded expression is:

8a^2y^2 - 10ay^2 - 3y^2 + 16a^2y - 20ay - 6y - 192a^2 + 240a + 72