Question

(х+4)(х-1)=х-(х-2)(2-х)

Answer 1

Ответ:

1 1/3

Объяснение:

(x+4)(x-1)=x-(x-2)(2-x)

x²-x+4x-4=x+(x-2)(x-2)

x²+3x-4=x+(x-2)²

x²+3x-4=x+x²-4x+4

x²+3x-4=x²-3x+4

x²+3x-x²+3x=4+4

6x=8

x=8/6=4/3=1 1/3

Answer 2

Let's solve the equation step by step:

1. Expand both sides of the equation:

On the left side, we have: (х+4)(х-1) = х^2 - х + 4х - 4

On the right side, we have: х - (х-2)(2-х) = х - (2-х)(х-2)

Now, expand the right side: х - (2-х)(х-2) = х - (2х - 2 - x^2 + 2x)

Simplify the right side further: х - (2х - 2 - x^2 + 2x) = х - 2х + 2 + x^2 - 2x

2. Now, let's set up the equation with the expanded expressions:

On the left side: х^2 - х + 4х - 4

On the right side: х - 2х + 2 + x^2 - 2x

3. Combine like terms on both sides:

On the left side: х^2 + 3х - 4

On the right side: х^2 - х - 2x + 2

4. Now, let's simplify further and move all terms to one side of the equation:

х^2 + 3х - 4 - (х^2 - х - 2x + 2) = 0

Now, subtract the right side from the left side:

х^2 + 3х - 4 - х^2 + х + 2x - 2 = 0

5. Combine like terms:

3х - 4 - 2 = 0

3х - 6 = 0

6. Now, isolate "х" by adding 6 to both sides:

3х = 6

7. Finally, divide both sides by 3 to solve for "х":

х = 6 / 3

х = 2

So, the solution to the equation is х = 2.