Question

Спростити вирази: a) √4c-√81c-√9c b) (1 -5√a)^2+10√a

Answer 1

Ответ:

a) -10c b) 1+25a

Объяснение:

$b) (1 -5\sqrt{a})^{2}+10\sqrt{a}=1^{2} - 2*1*5\sqrt{a}+(5\sqrt{a})^{2}+10\sqrt{a} =1 - 10\sqrt{a} +25a+10\sqrt{a}=\\=1+25a$

$a)\sqrt{4} c-\sqrt{81}c-\sqrt{9}c = 2c - 9c - 3c = - 10c$

Answer 2

a) √4c - √81c - √9c

First, simplify the square roots:

√4c = 2√c √81c = 9√c √9c = 3√c

Now, substitute these values back into the expression:

2√c - 9√c - 3√c

Combine like terms:

(2 - 9 - 3)√c

Simplify the constants:

(-10)√c

So, the simplified expression is -10√c.

b) (1 - 5√a)^2 + 10√a

First, square the binomial (1 - 5√a)^2:

(1 - 5√a)^2 = 1 - 10√a + 25a

Now, add 10√a to this expression:

1 - 10√a + 25a + 10√a

Notice that -10√a and 10√a cancel each other out, leaving you with:

1 + 25a

So, the simplified expression is 1 + 25a.