Question

СРОЧНО!!!y=x^2+3x-4 x0=1​

Answer 1

Ответ:  y(1)=0 .

$y=x^2+3x-4\ \ ,\ \ x_0=1\\\\y(1)=1^2+3\cdot 1-4=1+3-4=4-4=0$

Answer 2

Ответ:

На картинке

Объяснение:

Понятия не имею какое у вас задание, поэтому прислал два возможных решения данного примера

Answer 3

Looks like you've got an urgent quadratic equation on your hands! If you need to find the value of the equation $y = x^2 + 3x - 4$ when $x = 1$, just substitute $x = 1$ into the equation:

$y = (1)^2 + 3(1) - 4$

Now, just do the math and you'll have your answer! Let me know if you need help with the calculations.