Question

(х-2)(х^2+3х-4)=0 Help me!

Answer 1

Надеюсь, все понятно!

Answer 2

Certainly! To solve the equation (x-2)(x^2+3x-4) = 0, you can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.

So, in this case, you have:

1. (x-2) = 0
2. (x^2+3x-4) = 0

Now, let's solve each of these equations separately:

1. (x-2) = 0: Add 2 to both sides to isolate x: x - 2 + 2 = 0 + 2 x = 2

2. (x^2+3x-4) = 0: This is a quadratic equation, and it can be factored or solved using the quadratic formula.

   Factoring: (x^2+3x-4) = 0 can be factored as (x+4)(x-1) = 0.

   Now, set each factor equal to zero: x+4 = 0 and x-1 = 0

   Solve for x in each equation: For x+4 = 0, subtract 4 from both sides: x + 4 - 4 = 0 - 4 x = -4

   For x-1 = 0, add 1 to both sides: x - 1 + 1 = 0 + 1 x = 1

So, there are three solutions to the equation (x-2)(x^2+3x-4) = 0:

x = 2, x = -4, and x = 1.