Question

X^2+x-12/x+4=0.......​

Answer 1

Ответ:

надеюсь правильно, но думаю лучше проверить.

Answer 2

To solve the equation $\frac{x^2 + x - 12}{x + 4} = 0$, you can follow these steps:

1. First, factor the numerator $x^2 + x - 12$:

   $x^2 + x - 12 = (x + 4)(x - 3)$

2. Now, the equation becomes:

   $\frac{(x + 4)(x - 3)}{x + 4} = 0$

3. Since you have a common factor of $x + 4$ in both the numerator and denominator, you can cancel it out:

   $x - 3 = 0$

4. Now, isolate $x$ by adding 3 to both sides:

   $x = 3$

So, the solution to the equation $\frac{x^2 + x - 12}{x + 4} = 0$ is $x = 3$.