Question

10y²-0.8 y =1.92 плиз​

Answer 1

Ответ:

y₁ = 12/25

y₂= -2/5

Объяснение:

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10y² - 0,8y = 1,92

10y² - 0,8y - 1,92 = 0

D = (-0,8)² - 4 * 10 * (-1,92) = 0,64 + 76,8 = 77,44 (8,8²)

y₁ = (0,8 + 8,8)/(2 * 10) = 9,6/20 = 96/200 = 12/25

y₂ = (0,8 - 8,8)/(2 * 10) = -8/20 = -2/5

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Answer 2

To solve the quadratic equation $10y^2 - 0.8y = 1.92$, we'll first rearrange it into a standard quadratic form ($ax^2 + bx + c = 0$) and then use the quadratic formula to find the solutions for $y$.

The given equation is: $10y^2 - 0.8y = 1.92$

We'll rearrange it to the standard quadratic form: $10y^2 - 0.8y - 1.92 = 0$

Now, we can use the quadratic formula to solve for $y$: $y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = 10$, $b = -0.8$, and $c = -1.92$.

Substitute these values into the quadratic formula and calculate: $y = \frac{-(-0.8) \pm \sqrt{(-0.8)^2 - 4 \times 10 \times (-1.92)}}{2 \times 10}$

$y = \frac{0.8 \pm \sqrt{0.64 + 76.8}}{20}$

$y = \frac{0.8 \pm \sqrt{77.44}}{20}$

$y = \frac{0.8 \pm 8.801}{20}$

Now, calculate both solutions for $y$:

$y_1 = \frac{0.8 + 8.801}{20} \approx 0.539$ $y_2 = \frac{0.8 - 8.801}{20} \approx -0.46$

So, the solutions for $y$ are approximately $0.539$ and $-0.46$.