Question

(3х*2 +4)*2-10(3х*2+4)+21=0

Answer 1

Ответ:

3x^2+4-30x^2-40+21=0

-27x^2-15=0

9x^2+5=0

9x^2=-5

x(R

Объяснение:

Answer 2

To solve the equation (3x^2 + 4) * 2 - 10(3x^2 + 4) + 21 = 0, you can follow these steps:

1. Distribute the constants on both sides of the equation: 2(3x^2 + 4) - 10(3x^2 + 4) + 21 = 0

2. Simplify by combining like terms: 6x^2 + 8 - 30x^2 - 40 + 21 = 0

3. Combine the x^2 terms and constants: -24x^2 - 11 = 0

4. Add 11 to both sides of the equation to isolate the quadratic term: -24x^2 = 11

5. Divide by -24 to solve for x^2: x^2 = -11/24

6. To find x, take the square root of both sides. Keep in mind that there will be both positive and negative solutions: x = ±√(-11/24)

Since the square root of a negative number is a complex number, the solutions for x will be complex numbers. So, the solutions are:

x = √(11/24)i and x = -√(11/24)i, where "i" represents the imaginary unit.